I itsrayex New member Joined Jan 18, 2022 Messages 26 Feb 3, 2022 #1 The result is 1/2 but I can't reach the same solution. Can you tell me what I did wrong and how to reach the correct solution? thank you
The result is 1/2 but I can't reach the same solution. Can you tell me what I did wrong and how to reach the correct solution? thank you
blamocur Elite Member Joined Oct 30, 2021 Messages 3,224 Feb 3, 2022 #2 You've made a mistake in the first expression of the second line.
D Deleted member 4993 Guest Feb 3, 2022 #3 \(\displaystyle \frac{1}{x-1} - \frac{2}{x^2 - 1}\) = \(\displaystyle \frac{1}{x-1} - \frac{2}{(x - 1)*(x+1)}\) = \(\displaystyle \frac{-2+ (x+1)}{(x - 1)*(x+1)}\) = \(\displaystyle \frac{x-1}{(x - 1)*(x+1)}\) = \(\displaystyle \frac{1}{x+1}\) ..........................continue
\(\displaystyle \frac{1}{x-1} - \frac{2}{x^2 - 1}\) = \(\displaystyle \frac{1}{x-1} - \frac{2}{(x - 1)*(x+1)}\) = \(\displaystyle \frac{-2+ (x+1)}{(x - 1)*(x+1)}\) = \(\displaystyle \frac{x-1}{(x - 1)*(x+1)}\) = \(\displaystyle \frac{1}{x+1}\) ..........................continue