how is this formula read in English?(oral) AD^2 = 8^2 + 4^2, AD = sqrt[8^2 + 4^2] = 3 sqrt[10]

[menkoi]

how is this formula read in English?(oral)

[math]AD^2 = 8^2 + 4^2\\ AD = \sqrt{8^2+4^2} = 3\sqrt{10}[/math]

 

[stapel]

how is this formula read in English?(oral)

[math]AD^2 = 8^2 + 4^2\\ AD = \sqrt{8^2+4^2} = 3\sqrt{10}[/math]

A D squared equals eight squared plus four squared.

A D equals the square root of eight squared plus four squared equals three square-root ten.

 

[khansaheb]

AD=8²+4²=3*√10

↑​

That is incorrect.

AD =√ [8²+4² ]= √ [64 + 16] = √80= √[5 * 16] = 4 *√5

 

[topsquark]

A D squared equals eight squared plus four squared.

A D equals the square root of eight squared plus four squared equals three square-root ten.

I am not saying that you are wrong, but I would modify that last to read:
"AD is equal to the square root of the quantity 8 squared plus 4 squared (end quantity) is equal to 3 square root of 10."

I was always taught to "group" everything inside of a function.

-Dan

 

[menkoi]

A D squared equals eight squared plus four squared.

A D equals the square root of eight squared plus four squared equals three square-root ten.

thanks.
Can there be or not be a hyphen between "square" and "root"?

 

[menkoi]

↑​

That is incorrect.

AD =√ [8²+4² ]= √ [64 + 16] = √80= √[5 * 16] = 4 *√5

thanks.
I haven't been recognized until you pointed.

 

[menkoi]

I am not saying that you are wrong, but I would modify that last to read:
"AD is equal to the square root of the quantity 8 squared plus 4 squared (end quantity) is equal to 3 square root of 10."

I was always taught to "group" everything inside of a function.

-Dan

thanks.
Should I add "quantity" immediately before and after the expression to indicate a group?
And, is "end quantity" omittable?