defeated_soldier
Junior Member
- Joined
- Apr 15, 2006
- Messages
- 130
There is an equation ax+by=c , which has solutions that are only positive integers . 'a' and 'b' can take values 1 or 2 . 'c' can take values 1,2 or 3 . How many different solution sets are possible ?
1) 1
2) 2
3)3
4)More than 3
My Solution :
a={1,2}
b={1,2}
c={1,2,3}
so , we can make 2 x 2 x 3 =12 equations . // method of indepency rule
My solution is wrong .
Question :
Q1 . where do you see mistake in my solution ....why its is wrong ?
Q2. what should be the correct approach then ?
1) 1
2) 2
3)3
4)More than 3
My Solution :
a={1,2}
b={1,2}
c={1,2,3}
so , we can make 2 x 2 x 3 =12 equations . // method of indepency rule
My solution is wrong .
Question :
Q1 . where do you see mistake in my solution ....why its is wrong ?
Q2. what should be the correct approach then ?
