How to determine whether a set spans in Rn

Idealistic

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In general, I'd like to know how to determine whether a set of m vectors spans in Rn. Do I have to look at the rank of the matrix that the vectors form?

Like if 3 vectors in R3, have a rank of 3, does this mean they span in R3?
 
A set of vectors spans if they can be expressed as linear combinations. Say we have a set of vectors we can call S in some vector space we can call V. The subspace, we can call W, that consists of all linear combinations of the vectors in S is called the spanning space and we say the vectors span W.

Here is an example of vectors in R^3.

Say we have V1=(1,1,2),   v2=(1,0,1),   v3=(2,1,3)\displaystyle V_{1}=(1,1,2), \;\ v_{2}=(1,0,1), \;\ v_{3}=(2,1,3)

We want to see if they span or not.

We have to find whether an arbitrary vector, say, b=(b1,b2,b3)\displaystyle b=(b_{1},b_{2},b_{3}) can be expressed as a linear combo b=k1v1+k2v2+k3v3\displaystyle b=k_{1}v_{1}+k_{2}v_{2}+k_{3}v_{3} of the vectors v1,v2,v3\displaystyle v_{1},v_{2},v_{3}.

Set up a system of equations in terms of the components:

(b1,b2,b3)=k1(1,1,2)+k2(1,0,1)+k3(2,1,3)\displaystyle (b_{1},b_{2},b_{3})=k_{1}(1,1,2)+k_{2}(1,0,1)+k_{3}(2,1,3)

(b1,b2,b3)=(k1+k2+2k3,   k1+k3,   2k1+k2+3k3)\displaystyle (b_{1},b_{2},b_{3})=(k_{1}+k_{2}+2k_{3}, \;\ k_{1}+k_{3}, \;\ 2k_{1}+k_{2}+3k_{3})

k1+k2+2k3=b1\displaystyle k_{1}+k_{2}+2k_{3}=b_{1}

k1      +k3=b2\displaystyle k_{1} \;\ \;\ +k_{3}=b_{2}

2k1+k2+3k3=b3\displaystyle 2k_{1}+k_{2}+3k_{3}=b_{3}

The system is consistent for all b1,b2,b3\displaystyle b_{1},b_{2},b_{3} iff the matrix of coefficients:

A=[112101213]\displaystyle A=\begin{bmatrix}1&1&2\\1&0&1\\2&1&3\end{bmatrix}

has a determinant that is not equal to 0.

But this determinant does equal 0, so it DOES NOT span.
 
Idealistic said:
In general, I'd like to know how to determine whether a set of m vectors spans in Rn. Do I have to look at the rank of the matrix that the vectors form?

Like if 3 vectors in R3, have a rank of 3, does this mean they span in R3?

I wouldn't want to say you had to look at the rank, but that will certainly do.

The columns - or rows - of a rank r matrix will span an r-dimensional space. If r=3 and the vectors are in R^3, then this must be the whole space.

However, that's not the only way to do it. For example, you could look at the null space, and use the rank-nullity theorem.
 
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