How to factor 4x(3x+1)^2 +6x^2?

[JustinK]

How to factor 4x(3x+1)^2 +6x^2?

We have to use the GCF method.
I found the GCF to be 2x. At a certain point I get 18x^2 + 2 + (3x) [with GCF in front].

Any help would be greatly appreciated!
Thank you!

 

[topsquark]

You got the right GCF! But FOIL out [imath](3x + 1)^2[/imath] again. What happened to the Outer and Inner terms?

-Dan

 

[Deleted member 4993]

We have to use the GCF method.
I found the GCF to be 2x. At a certain point I get 18x^2 + 2 + (3x) [with GCF in front].

Any help would be greatly appreciated!
Thank you!

18x^2 + 2 + (3x) is a quadratic function.

Do you know how to factorize a quadratic function?

 

[Steven G]

How to factor 4x(3x+1)^2 +6x^2?

We have to use the GCF method.
I found the GCF to be 2x. At a certain point I get 18x^2 + 2 + (3x) [with GCF in front].

Any help would be greatly appreciated!
Thank you!

(a+b)² is NOT a²+b²
25 = 5² = (3+2)² = 3²+ 2²= 9 + 4 = 13. Since 25 does not equal 13 at least one of those equal signs MUST be wrong. Find them!

 

[Harry_the_cat]

\(\displaystyle 4x(3x+1)^2 +6x^2\)
\(\displaystyle =2x[2(3x+1)^2+3x]\)
\(\displaystyle =2x[2(9x^2+6x+1)+3x]\) .... you had missed the middle term 6x (as Post#2 and #4 pointed out)
\(\displaystyle =2x[18x^2+12x+2+3x]\)
\(\displaystyle =2x[18x^2+15x+2]\)
\(\displaystyle = ... \) up to you now to factorise the quadratic.