Z Zamiii New member Joined Nov 22, 2018 Messages 1 Nov 22, 2018 #1 Hello When I differentiate (4t^(2/3))/(t^2+1) I get the numerator as 8/3t^(5/3)+8/3t^(-1/3)-8t^(5/3) How do I factorise this numerator to get 8/3t^(-1/3)(2t^2-1) (if that's correct) Thanks
Hello When I differentiate (4t^(2/3))/(t^2+1) I get the numerator as 8/3t^(5/3)+8/3t^(-1/3)-8t^(5/3) How do I factorise this numerator to get 8/3t^(-1/3)(2t^2-1) (if that's correct) Thanks
D Deleted member 4993 Guest Nov 22, 2018 #2 Zamiii said: Hello When I differentiate (4t^(2/3))/(t^2+1) I get the numerator as 8/3t^(5/3)+8/3t^(-1/3)-8t^(5/3) How do I factorise this numerator to get 8/3t^(-1/3)(2t^2-1) (if that's correct - it is correct) Thanks Click to expand... First factor out 8/3*t^(-1/3) - things will start to look much better.
Zamiii said: Hello When I differentiate (4t^(2/3))/(t^2+1) I get the numerator as 8/3t^(5/3)+8/3t^(-1/3)-8t^(5/3) How do I factorise this numerator to get 8/3t^(-1/3)(2t^2-1) (if that's correct - it is correct) Thanks Click to expand... First factor out 8/3*t^(-1/3) - things will start to look much better.
