how do I with only the lengths of the sides of a triangle find the angles of each side?
S s-bot-22 New member Joined Feb 11, 2015 Messages 2 Feb 11, 2015 #1 how do I with only the lengths of the sides of a triangle find the angles of each side?
Steven G Elite Member Joined Dec 30, 2014 Messages 14,587 Feb 11, 2015 #2 s-bot-22 said: how do I with only the lengths of the sides of a triangle find the angles of each side? Click to expand... You can use the law of cosines. c^2 = a^2 + b^2 -2abcosC. So cosC= [a^2 + b^2 -c^2]/(2ab) Hence C = arccos {[a^2 + b^2 -c^2]/(2ab)}
s-bot-22 said: how do I with only the lengths of the sides of a triangle find the angles of each side? Click to expand... You can use the law of cosines. c^2 = a^2 + b^2 -2abcosC. So cosC= [a^2 + b^2 -c^2]/(2ab) Hence C = arccos {[a^2 + b^2 -c^2]/(2ab)}
