How to find the gradient of curve (i)2x^3 + 5xy +y^3 = 8 (ii) x = 2(t -2)^3 - 16 and y= 2 sin t + cos t

there are no coordinate in this question ,Im stuck on both question (i) and (ii), this are the whole question , i already stuck when i see this question1627916208771.png
 
there are no coordinate in this question ,Im stuck on both question (i) and (ii), this are the whole question , i already stuck when i see this questionView attachment 28474
You are supposed to calculate those!

Hint:

When the curve crosses the y-axis, what is the x-co-ordinate of the point of intersection?

Now use the equation describing the curve and calculate the y-co-ordinate of the point of intersection?

Where is the definition of "gradient"?
 
What are the co-ordinates of the points where each graph cross y-axis?

What is the "definition" of the gradient of a curve?

View attachment 28473
(i) Have you learnt how to do implicit differentiation?
(ii) Find dx/dt and dy/dt, then use the chain rule to find dy/dx.

In both cases, the y-int is found by letting x=0, because all points on the y-axis have an x-coord of 0.
 
I think this student is not willing to show any work and expecting a "xerox-able" response, as evident from old posts.
 
Is x = f(y) or y = g(t) in the neighborhood of the points of investigation?
 
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