i dont understand how to find the square root of 225x to the third power
D daszy New member Joined Oct 17, 2006 Messages 2 Oct 17, 2006 #1 i dont understand how to find the square root of 225x to the third power
skeeter Elite Member Joined Dec 15, 2005 Messages 3,216 Oct 17, 2006 #2 \(\displaystyle \L \sqrt{225x^3} = \sqrt{15^2 \cdot x^2 \cdot x} = \sqrt{15^2}\sqrt{x^2}\sqrt{x} = 15|x|\sqrt{x}\)
\(\displaystyle \L \sqrt{225x^3} = \sqrt{15^2 \cdot x^2 \cdot x} = \sqrt{15^2}\sqrt{x^2}\sqrt{x} = 15|x|\sqrt{x}\)
tkhunny Moderator Staff member Joined Apr 12, 2005 Messages 11,339 Oct 18, 2006 #4 Always a dispute. In this case, the absolute values are not necessary. Additional information in the original expression and in the final expression, namely x\displaystyle \sqrt{x}x, already restricts to x≥0\displaystyle x \ge 0x≥0.
Always a dispute. In this case, the absolute values are not necessary. Additional information in the original expression and in the final expression, namely x\displaystyle \sqrt{x}x, already restricts to x≥0\displaystyle x \ge 0x≥0.
