P petr New member Joined Oct 22, 2015 Messages 24 Nov 2, 2015 #1 Hello, how to get the factor of this cubic equation: 2x^3-3x^2-3x+7 = f(x) I have tried to get the zero with this range of numbers [1,7,-1,7] but never got it. I noticed it is odd number. that is what make me confused a bit. Thankx
Hello, how to get the factor of this cubic equation: 2x^3-3x^2-3x+7 = f(x) I have tried to get the zero with this range of numbers [1,7,-1,7] but never got it. I noticed it is odd number. that is what make me confused a bit. Thankx
D Deleted member 4993 Guest Nov 2, 2015 #2 petr said: Hello, how to get the factor of this cubic equation: 2x^3-3x^2-3x+7 = f(x) I have tried to get the zero with this range of numbers [1,7,-1,7] but never got it. I noticed it is odd number. that is what make me confused a bit. Thankx Click to expand... Did you try plotting it?
petr said: Hello, how to get the factor of this cubic equation: 2x^3-3x^2-3x+7 = f(x) I have tried to get the zero with this range of numbers [1,7,-1,7] but never got it. I noticed it is odd number. that is what make me confused a bit. Thankx Click to expand... Did you try plotting it?
D Deleted member 4993 Guest Nov 2, 2015 #3 This function does not have a rational root. It has one real root estimated to be = - 1.39015
