S Stelyios New member Joined Oct 2, 2015 Messages 1 Oct 2, 2015 #1 ∫(x*sin2(x))/(x3-1) over the terminals: b= ∞ and a = 2 I have this improper integral and am absolutely stuck on how to approach it.. I need to prove its convergence or divergence
∫(x*sin2(x))/(x3-1) over the terminals: b= ∞ and a = 2 I have this improper integral and am absolutely stuck on how to approach it.. I need to prove its convergence or divergence
I Ishuda Elite Member Joined Jul 30, 2014 Messages 3,342 Oct 2, 2015 #2 Stelyios said: ∫(x*sin2(x))/(x3-1) over the terminals: b= ∞ and a = 2 I have this improper integral and am absolutely stuck on how to approach it.. I need to prove its convergence or divergence Click to expand... Hint: Absolute convergence implies convergence and \(\displaystyle |\frac{x\, sin^2(x)}{x^3\, -1}|\, \le\, \frac{x}{x^3\, -1}\, for\, x\, \ge\, 2\)
Stelyios said: ∫(x*sin2(x))/(x3-1) over the terminals: b= ∞ and a = 2 I have this improper integral and am absolutely stuck on how to approach it.. I need to prove its convergence or divergence Click to expand... Hint: Absolute convergence implies convergence and \(\displaystyle |\frac{x\, sin^2(x)}{x^3\, -1}|\, \le\, \frac{x}{x^3\, -1}\, for\, x\, \ge\, 2\)