How to prove (cot^2x+1)(sin^2x+1)=cot^2 x+2

[Tennis44]

(cot^2x+1)(sin^2x+1)=cot^2 x+2

 

[Deleted member 4993]

(cot^2x+1)(sin^2x+1)=cot^2 x+2

Is the expression in your problem

$\displaystyle cot^2(x+1) * sin^2(x+1) \ = \ cot^2(x+2)$

 

[Tennis44]

 

[Deleted member 4993]

Prove that: (cot²Θ + 1)(sin²Θ +1) = cot²Θ + 2 [ Hint: multiply out the left-hand-side]

What are your thoughts?

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[Tennis44]

Precal identities


[ cos²x/sin² x + 1 ] [ sin²x + 1 ] I got this far and now I'm stuck.

 

[Deleted member 4993]

Precal identities


[ cos²x/sin² x + 1 ] [ sin²x + 1 ] I got this far and now I'm stuck.

multiply it out - like (a+b)(c+d) = a*c + a*d + b*c + b*d