the differential equation is
dy/dx + 1 = ex-y
I have tried this
dy/dx + 1 = ex-y ......equation 1
or, dy/dx=ex-y-1
taking x-y=v ....equation 2
differentiating eqn 2 with respect to x, we get:
1-dy/dx=dv/dx
or,dy/dx=1-dv/dx
or,ev-1=1-dv/dx
or,2-ev=dv/dx
or,dv/2-ev=dx
i am stuck here. i think this may be simple if i have not mistaken above. can you please help me...
dy/dx + 1 = ex-y
I have tried this
dy/dx + 1 = ex-y ......equation 1
or, dy/dx=ex-y-1
taking x-y=v ....equation 2
differentiating eqn 2 with respect to x, we get:
1-dy/dx=dv/dx
or,dy/dx=1-dv/dx
or,ev-1=1-dv/dx
or,2-ev=dv/dx
or,dv/2-ev=dx
i am stuck here. i think this may be simple if i have not mistaken above. can you please help me...
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