S sonithcob New member Joined Apr 18, 2016 Messages 1 Apr 18, 2016 #1 How to solve this differntial equation? dy/dt = (2-y)(5-y)
D Deleted member 4993 Guest Apr 18, 2016 #2 sonithcob said: How to solve this differntial equation? dy/dt = (2-y)(5-y) Click to expand... Hint: \(\displaystyle \dfrac{1}{(2-y)(5-y)} \ = \ \dfrac{1}{3} * \left [ \dfrac{1}{2-y} \ - \ \dfrac{1}{5-y} \right ] \)
sonithcob said: How to solve this differntial equation? dy/dt = (2-y)(5-y) Click to expand... Hint: \(\displaystyle \dfrac{1}{(2-y)(5-y)} \ = \ \dfrac{1}{3} * \left [ \dfrac{1}{2-y} \ - \ \dfrac{1}{5-y} \right ] \)
stapel Elite Member Joined Feb 4, 2004 Messages 16,543 Apr 18, 2016 #3 sonithcob said: How to solve this differntial equation? dy/dt = (2-y)(5-y) Click to expand... In case you're not sure what's going on in the first reply you received, think "partial fractions" (here).
sonithcob said: How to solve this differntial equation? dy/dt = (2-y)(5-y) Click to expand... In case you're not sure what's going on in the first reply you received, think "partial fractions" (here).
O oscarguevara New member Joined May 1, 2016 Messages 2 May 1, 2016 #4 sonithcob said: How to solve this differntial equation? dy/dt = (2-y)(5-y) Click to expand... dt= - (2-y) + (5-y) -2 /(2-y)(5-y) t=ln(5-y)/(2-y) 2e^t - ye^t=5-y 2e^t -5= y(e^t - 1) y=(2e^t -5)/y(e^t - 1) i allways forget the constant
sonithcob said: How to solve this differntial equation? dy/dt = (2-y)(5-y) Click to expand... dt= - (2-y) + (5-y) -2 /(2-y)(5-y) t=ln(5-y)/(2-y) 2e^t - ye^t=5-y 2e^t -5= y(e^t - 1) y=(2e^t -5)/y(e^t - 1) i allways forget the constant