How to sum a Bernoulli probability: Let's assume that we're throwing a dice....

anonymous2

New member
Joined
Oct 21, 2016
Messages
15
Hello Everybody.

I'm not good enough about probability and my problem is that I can't sum up bernoulli probability.

Let's assume that we're throwing a dice.
1 step. Probability of succes in first try is 1/6.
2 step. Now we're choosing 2 walls, so probability of succes is 2/6.
3 step. Now 3 walls, so probability of succes in third is 3/6.

Can I just sum it up? then I will receive probability equal 1. But it isn't true. If I bet wall with 1 in first trial, on second I bet wall with 1,2. In third trial I bet wall with 1,2,3. The probability is 1 but it is very possible that during the 3 throws I will not receive any of these walls.
 
I'm not good enough about probability and my problem is that I can't sum up bernoulli probability.

Let's assume that we're throwing a dice.
Are we to assume that the die is six-sided and fair?

1 step. Probability of succes in first try is 1/6.
How is "success" defined? Rolling a "1"? Or something else?

2 step. Now we're choosing 2 walls, so probability of succes is 2/6.
3 step. Now 3 walls, so probability of succes in third is 3/6.
What are the "walls", and how do they relate to the die?

Can I just sum it up? then I will receive probability equal 1. But it isn't true. If I bet wall with 1 in first trial, on second I bet wall with 1,2. In third trial I bet wall with 1,2,3. The probability is 1 but it is very possible that during the 3 throws I will not receive any of these walls.
What, exactly, are you trying to accomplish? What was the full and exact text of the exercise? What were the instructions?

Please be complete. Thank you! ;)
 
my problem is that I can't sum up bernoulli probability.
Let's assume that we're throwing a dice.
1 step. Probability of succes in first try is 1/6.
2 step. Now we're choosing 2 walls, so probability of succes is 2/6.
3 step. Now 3 walls, so probability of succes in third is 3/6.
What in the world do walls have to do with dice?
You need to define you terms.
 
Hello Everybody.

I'm not good enough about probability and my problem is that I can't sum up bernoulli probability.

Let's assume that we're throwing a dice.
Actually, you can't. You can throw a "die". "Dice" is the plural of "die".

1 step. Probability of succes in first try is 1/6.
Assuming a fair 6 sided die, yes, if by "success" you mean getting a specific number.

2 step. Now we're choosing 2 walls, so probability of succes is 2/6.
"Walls"? Do you mean "values"? If "success" means getting either of two values (from 1 to 6), the probability is 2/6= 1/3/

3 step. Now 3 walls, so probability of succes in third is 3/6.
If you mean getting one of 3 given values, yes, the probability is 3/6= 1/2.

Can I just sum it up? then I will receive probability equal 1. But it isn't true. If I bet wall with 1 in first trial, on second I bet wall with 1,2. In third trial I bet wall with 1,2,3. The probability is 1 but it is very possible that during the 3 throws I will not receive any of these walls.

To answer what question? Sum those up to get what?
 
Top