Express a through c and b through c. Plug in the resulting expressions into the left side of the 3rd equality, simplify. Do you get 29/34?View attachment 37261
I was able to combine the a's, b's and c's into one ratio
View attachment 37262
But I am stuck on how to do the numbers side.
I do have the answer scheme, which is this below, but I don't really understand how they got the answer:
View attachment 37263
Can anyone explain, please?
It might be easier to look at it in fractions.View attachment 37261
I was able to combine the a's, b's and c's into one ratio
View attachment 37262
But I am stuck on how to do the numbers side.
I do have the answer scheme, which is this below, but I don't really understand how they got the answer:
View attachment 37263
Can anyone explain, please?
In the context of ratios, I don't see any case that could be ambiguous, ergo no need for parenthesis. Can you think of a case where it's ambiguous?P.S. Is this standard notation not to use parentheses in a + b : b + c????
This is an actual question from last year's GCSE exam (Higher Maths) in England, paper 2. I don't think we've been taught to use parentheses in such cases, no. But this is quite an unusual ratio question to be honest, compared to the ones from the past papers - one of the rare tricky ones.Express a through c and b through c. Plug in the resulting expressions into the left side of the 3rd equality, simplify. Do you get 29/34?
P.S. Is this standard notation not to use parentheses in a + b : b + c????
I get the first part of your explanation. I don't really get the second step though. Can you explain how you got that?It might be easier to look at it in fractions.
9a:7c=4:7⟹7c9a=74⟹ca=97×74=94⟹a:c=4:9
A similar process for the second ratio to arrive at b:c=25:9
The second step. For every 9c, how many b do you have?
9c×9c25b=25b⟹a:b:c=4:25:9
I think the last part is self-explanatory.
Looking at 2 ratios from step 1 i.e. a:c=4:9 and b:c=25:9I get the first part of your explanation. I don't really get the second step though. Can you explain how you got that?
Ah, got it. Thank you. Thank you both for your explanations. Both of you helped me understand how to do this question.Looking at 2 ratios from step 1 i.e. a:c=4:9 and b:c=25:9
Since c is common in both ratios, I'm looking to relate the two. From ratio 1, for every 4a, I get 9c. If I have 9c, how many b's do I get? The second ratio tells me for every 9c I get 25b.