P Panama New member Joined Nov 29, 2008 Messages 29 Dec 7, 2008 #1 Solve x= -4?x+12 x - 12 = -4?x square both sides x^2 - 24x + 144 = 16x x^2 - 40x + 144 = 0 (x-4)(x-36) = 0-->x = 4, x =36
Solve x= -4?x+12 x - 12 = -4?x square both sides x^2 - 24x + 144 = 16x x^2 - 40x + 144 = 0 (x-4)(x-36) = 0-->x = 4, x =36
D Deleted member 4993 Guest Dec 7, 2008 #2 Panama said: Solve x= -4?x+12 x - 12 = -4?x square both sides x^2 - 24x + 144 = 16x x^2 - 40x + 144 = 0 (x-4)(x-36) = 0-->x = 4, x =36 Click to expand... You can check it yourself. Put these values of 'x' in your original equation - and see if the equality is satisfied. If the equality is satisfied - most probably you are correct. If the equality is not satisfied - most probably you are incorrect or you got a superfluous (extreneous)solution due to "squaring". Show us what do you get.
Panama said: Solve x= -4?x+12 x - 12 = -4?x square both sides x^2 - 24x + 144 = 16x x^2 - 40x + 144 = 0 (x-4)(x-36) = 0-->x = 4, x =36 Click to expand... You can check it yourself. Put these values of 'x' in your original equation - and see if the equality is satisfied. If the equality is satisfied - most probably you are correct. If the equality is not satisfied - most probably you are incorrect or you got a superfluous (extreneous)solution due to "squaring". Show us what do you get.
