# I have this question I'm just wondering how to solve it: Given f(x) = x^2 - 6x + 10. If f(a) = 1, find the value of 'a'.

#### Alex.Jorgin

##### New member
I have this question I'm just wondering how to solve it.

here is the question:

Given: f(x) = x^2 - 6x + 10

if f(a) = 1, what is the value of a?

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here is the question:

Given: f(x) = x^2 - 6x + 10

if f(a) = 1, what is the value of a?
The equation [imath]f(a) = 1[/imath] means $a^2-6a+10=1$
So, solve that equation.

If you have trouble doing that, please show us what you have tried, so we can see what sort of help you need:

Whenever you are stuck you should look at the definitions. As Dr Peterson pointed out, f(a) = a2 - 6a + 10 and is given to equal 1

I have this question I'm just wondering how to solve it.

here is the question:

Given: f(x) = x^2 - 6x + 10

if f(a) = 1, what is the value of a?
You've been told that The equation [imath]f(a) = 1[/imath] means:-

$a^2-6a+10=1$
But that also means that:-
$a^2-6a+9=0$
Can you factorise that equation? To get:-

[imath](a\,\pm\,?)(a\,\pm\,?)=0[/imath]
(Replacing each "[imath]\pm\,?[/imath]" with an appropriate value.)

Do you know what the Discriminant is?
(And what its significance is?)
In this case it is zero; what does that tell you?

Hope that helps.