I need explanation and steps for this!

If I understood the question correctly, then the equation has the general form of [imath]y=k\sqrt{x}[/imath].
When x=5 and y = 35, you have [imath]35=k\sqrt{5} [/imath]. Can you solve for k? After that, you can plug in k and x=22 in the general form and solve for y.
 
BigBeachBanana said:
If I understood the question correctly, then the equation has the general form of [imath]y=k\sqrt{x}[/imath].
When x=5 and y = 35, you have [imath]35=k\sqrt{5} [/imath]. Can you solve for k? After that, you can plug in k and x=22 in the general form and solve for y.
Click to expand...
I realize that the answer is listed in terms of [imath]\sqrt{x}[/imath], but if y varies directly with x then y = kx.

-Dan
 
topsquark said:
I realize that the answer is listed in terms of [imath]\sqrt{x}[/imath], but if y varies directly with x then y = kx.

-Dan
Click to expand...
So, why is [imath]\sqrt{x}[/imath] there, and what equation is it saying to solve?

1644846291053.png​

I think the question is defective, or at least misleading.
 
To be crystal clear, there is a typo in the problem and where it says sqrt(x) it should just be x.
 
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