I need help with an integration problem

doniarahhal

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Aug 12, 2020
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Does any one know how can you solve this equation
∫_0^(π/2)▒cot⁡〖θd θ〗
the integral from 0 to π/2 of cotθ dθ.
any help would be appreciated
thank you
 
0π/2cot(θ)dθ\displaystyle \int_0^{\pi/2} \cot(\theta)d\theta.

I recall that cot(θ)=cos(θ)sin(θ)\displaystyle \cot(\theta)= \frac{\cos(\theta)}{\sin(\theta)}
so that the integral can be written 0π/2cos(θ)sin(θ)dθ\displaystyle \int_0^{\pi/2} \frac{\cos(\theta)}{\sin(\theta)}d\theta.

I also recall that the derivative of sin(θ)\displaystyle \sin(\theta) is cos(θ)\displaystyle \cos(\theta) and that makes me think of the substitution u=sin(θ)\displaystyle u= \sin(\theta).

What do you get when you make that substitution?

(Oh dear, oh dear, oh dear- there is a problem at θ=0\displaystyle \theta= 0!)
 
Does any one know how can you solve this equation
∫_0^(π/2)▒cot⁡〖θd θ〗
the integral from 0 to π/2 of cotθ dθ.
any help would be appreciated
thank you
So, have you learned anything about improper integrals?
 
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