The perimeter of triDOG is 33. If DO=10 and DG=12, find the larger of the two segments into which the third side is divided by the angle bisector of <ODG.
1--Let P be the point where the biscrtor of /_ODG intercepts OG
2--Find all three angles bt means of the Law of Cosines.
3--Havine the three angles of the two triangles formed by the bisector, find OP and PG by means of the Law of sinne.
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