I need you help ! Please. Thank you!

[lovehearts1000]

1. Given the y=x^2-4 and y=-x-2, solve the system of nonlinear equation.

A. 1, −3, (−2, 0)

B. (1,-3),(-2,1)

C. (1,-3),(-2,2)

D. (1,-3),(-2,3)

2. Given the x^2+y^2=-1 and x^2+〖(y+2)〗^2=9, solve the system of nonlinear equation.

A. (0, 1)

B. (0, 2)

C. (0,3)

D. (0,4)

3. Given the y=x^2-2x+2 and y=2x-2, solve the system of nonlinear equation.

A. (2, 3)

B. (−2, 3)

C. (2,2)

D. (2,-2)

4. Given the y=x^2-x-6 and y=2x-2, solve the system of nonlinear equation.

A. 4, 6, (1, −4)

B. −4, 6, (−1, −4)

C. (4,6),(-1,4)

D. (4,6),(-1,-4)

5. Given the x^2+2x-y+1=0 and x+y-1=0, solve the system of nonlinear equation.

A. (x=3,y=4),(x=0,y=-1)

B. (x=-3,y=4),(x=0,y=1)

C. (x=3,y=-4),(x=0,y=1)

D. (x=3,y=4),(x=0,y=1)

6. Given the x^2+4x-y+3=0 and x-y+7=0, solve the system of nonlinear equation.

A. (1,8), (-2, 3)

B. (1, 8), (-4, 5)

C. (1, 8), (-4, 4)

D. (1, 8), (-4, 3)

7. Given the x^2+y^2-8x-4=0 and 2x-y-18=0, solve the system of nonlinear equation.

A. (8, -2)

B. (8, -1)

C. (8, -3)

D. (8, -4)

8. Given the y=〖(x-1)〗^3 and y=x-1, solve the system of nonlinear equation.

A. (0, -1), (1, 1), (2, 1)

B. (0, -1), (1, 0), (3, 1)

C. (0, -1), (1, 0), (2, 2)

D. (0, -1), (1, 0), (2, 1)

9. Given the x^3-9x^2+24x-y=0 and x-y+15=0, solve the system of nonlinear equation.

A. (1, 16), (3, 18), (5, 20)

B. (1, 16), (3, 18), (5, 18)

C. (1, 16), (3, 18), (5, 19)

D. (1, 16), (3, 18), (5, 21)

10. Given the 3-x^2=y^2and x+1=y, solve the system of nonlinear equation.

A. (-2, -1), (1, 1)

B. (-2, -1), (1, 4)

C. (-2, -1), (1, 2)

D. (-2, -1), (1, 3)

 

[Harry_the_cat]

These are pretty much all the same. Take the point/s. Substitute into the equation/s. Remember that first coordinate is x and second is y. Do you end up with true statement/s? If yes, then it is a solution, If not, it isn't. Give it a go and then show us if you are still stuck.

 

[lex]

To solve, remove one of the variables by re-arranging one of the equations, if necessary, and substituting this into the other equation.
E.g. Question 7 [MATH]\qquad x^2+y^2-8x-4=0[/MATH] and [MATH]2x-y-18=0[/MATH]
The second equation rearranges to give: [MATH]\qquad y=2x-18[/MATH]Substitute this into the first equation to get: [MATH]\qquad x^2+\left(2x-18\right)^2-8x-4=0[/MATH]Solve this quadratic equation and then use [MATH]y=2x-18[/MATH] to find the corresponding value(s) of [MATH]y[/MATH].

 

[Deleted member 4993]

1. Given the y=x^2-4 and y=-x-2, solve the system of nonlinear equation.

A. 1, −3, (−2, 0)

B. (1,-3),(-2,1)

C. (1,-3),(-2,2)

D. (1,-3),(-2,3)

2. Given the x^2+y^2=-1 and x^2+〖(y+2)〗^2=9, solve the system of nonlinear equation.

A. (0, 1)

B. (0, 2)

C. (0,3)

D. (0,4)

3. Given the y=x^2-2x+2 and y=2x-2, solve the system of nonlinear equation.

A. (2, 3)

B. (−2, 3)

C. (2,2)

D. (2,-2)

4. Given the y=x^2-x-6 and y=2x-2, solve the system of nonlinear equation.

A. 4, 6, (1, −4)

B. −4, 6, (−1, −4)

C. (4,6),(-1,4)

D. (4,6),(-1,-4)

5. Given the x^2+2x-y+1=0 and x+y-1=0, solve the system of nonlinear equation.

A. (x=3,y=4),(x=0,y=-1)

B. (x=-3,y=4),(x=0,y=1)

C. (x=3,y=-4),(x=0,y=1)

D. (x=3,y=4),(x=0,y=1)

6. Given the x^2+4x-y+3=0 and x-y+7=0, solve the system of nonlinear equation.

A. (1,8), (-2, 3)

B. (1, 8), (-4, 5)

C. (1, 8), (-4, 4)

D. (1, 8), (-4, 3)

7. Given the x^2+y^2-8x-4=0 and 2x-y-18=0, solve the system of nonlinear equation.

A. (8, -2)

B. (8, -1)

C. (8, -3)

D. (8, -4)

8. Given the y=〖(x-1)〗^3 and y=x-1, solve the system of nonlinear equation.

A. (0, -1), (1, 1), (2, 1)

B. (0, -1), (1, 0), (3, 1)

C. (0, -1), (1, 0), (2, 2)

D. (0, -1), (1, 0), (2, 1)

9. Given the x^3-9x^2+24x-y=0 and x-y+15=0, solve the system of nonlinear equation.

A. (1, 16), (3, 18), (5, 20)

B. (1, 16), (3, 18), (5, 18)

C. (1, 16), (3, 18), (5, 19)

D. (1, 16), (3, 18), (5, 21)

10. Given the 3-x^2=y^2and x+1=y, solve the system of nonlinear equation.

A. (-2, -1), (1, 1)

B. (-2, -1), (1, 4)

C. (-2, -1), (1, 2)

D. (-2, -1), (1, 3)

I suspect that there is a typo in the second problem. You write:

x^2 + y^2 = - 1

That equation does not have real solution.