If F(x) = f(g(x)), g(2)=6, g'(2)=4, and f'(6)=108, find F'(2

[skor]

If F(x) = f(g(x)), where g(2)=6, g'(2)=4, and f'(6)=108, Find F'(2).

The answer is 432.

How would I about to finding this out?

 

[pka]

\(\displaystyle \L F(x) = f(g(x))\quad \Rightarrow \quad F'(x) = f'(g(x))g'(x)\)

 

[arthur ohlsten]

F(x)=f(g(x))
F'(x)=f'(g(x))times g'(x)
F'(2)=g'(2) f'(g(2))
F'(2) = 4 f'(6)
F'(2)=4[108]
F'(2)=432

Arthur

 

[skor]

Ahh thanks alot, I see what I was doing wrong now.

 

[arthur ohlsten]

You are more than welcome
Good luck with your studies
Arthur