D dagr8est Junior Member Joined Nov 2, 2004 Messages 128 Sep 23, 2005 #1 If a and b are real numbers, i^2=-1, and (a+b)+5i=9+ai, what is the value of b? a)4 b)5 c)9 d)4+5i e)5+4i This looks simple enough but I can't figure out how to get rid of the a.
If a and b are real numbers, i^2=-1, and (a+b)+5i=9+ai, what is the value of b? a)4 b)5 c)9 d)4+5i e)5+4i This looks simple enough but I can't figure out how to get rid of the a.
pka Elite Member Joined Jan 29, 2005 Messages 11,978 Sep 23, 2005 #2 Look at this: (a+b)+5i=9+ai. So if a=5, what is b?
D dagr8est Junior Member Joined Nov 2, 2004 Messages 128 Sep 23, 2005 #3 Aw man, I cannot believe I didn't see that. I was wondering why brackets were included. Thanks, that makes it so easy now.
Aw man, I cannot believe I didn't see that. I was wondering why brackets were included. Thanks, that makes it so easy now.
