Y yanarains New member Joined Sep 27, 2007 Messages 25 Oct 10, 2007 #1 Given 12x2 + y2 = 21 Use implicit differentiation to find dy/dx and evaluate it at (1, 3) My work: (24x+2y)dy/dx=0 dy/dx= -x/y= -1/3=-.333 What is the correct way to solve this equation? Thank you
Given 12x2 + y2 = 21 Use implicit differentiation to find dy/dx and evaluate it at (1, 3) My work: (24x+2y)dy/dx=0 dy/dx= -x/y= -1/3=-.333 What is the correct way to solve this equation? Thank you
D Deleted member 4993 Guest Oct 10, 2007 #2 yanarains said: Given 12x2 + y2 = 21 Use implicit differentiation to find dy/dx and evaluate it at (1, 3) My work: (24x+2y)dy/dx=0 dy/dx= -x/y= -1/3=-.333 What is the correct way to solve this equation? Thank you Click to expand... You need to review this part: \(\displaystyle \frac{d}{dx} (12x^2+y^2)\) = \(\displaystyle 24x + 2y\cdot\frac{dy}{dx}\) then \(\displaystyle 24x + 2y\cdot\frac{dy}{dx}\) = 0 \(\displaystyle \frac{dy}{dx}\) = -\(\displaystyle 12\cdot\frac{x}{y}\) Now evaluate \(\displaystyle \frac{dy}{dx}\)
yanarains said: Given 12x2 + y2 = 21 Use implicit differentiation to find dy/dx and evaluate it at (1, 3) My work: (24x+2y)dy/dx=0 dy/dx= -x/y= -1/3=-.333 What is the correct way to solve this equation? Thank you Click to expand... You need to review this part: \(\displaystyle \frac{d}{dx} (12x^2+y^2)\) = \(\displaystyle 24x + 2y\cdot\frac{dy}{dx}\) then \(\displaystyle 24x + 2y\cdot\frac{dy}{dx}\) = 0 \(\displaystyle \frac{dy}{dx}\) = -\(\displaystyle 12\cdot\frac{x}{y}\) Now evaluate \(\displaystyle \frac{dy}{dx}\)
D Dr. Flim-Flam Junior Member Joined Oct 10, 2007 Messages 108 Oct 10, 2007 #3 Given: 12x²+y² = 21, find the slope at (1,3). 24x+2yy' = 0, 2yy' = -24x, y'=-24x/2y = -12x/y, = -4 at (1,3). Note: Can also be solved explicitly, to wit: y² = 21-12x², y = ±√(21-12x²), y'=-24x/2±√(21-12x²) = -12x/±√(21-12x²). When x = 1, y' = -12/±3 = -4 or 4. Disregard 4 (extraneous solution).
Given: 12x²+y² = 21, find the slope at (1,3). 24x+2yy' = 0, 2yy' = -24x, y'=-24x/2y = -12x/y, = -4 at (1,3). Note: Can also be solved explicitly, to wit: y² = 21-12x², y = ±√(21-12x²), y'=-24x/2±√(21-12x²) = -12x/±√(21-12x²). When x = 1, y' = -12/±3 = -4 or 4. Disregard 4 (extraneous solution).