Impossible proof, please help

j_mccarthy2

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I am having extreme difficulty with this. I've tried using inscribed angle theorems, but I've given up. Can anyone solve this?
 
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I am having extreme difficulty with this. I've tried using inscribed angle theorems, but I've given up. Can anyone solve this?

I suggest you think about showing that triangles BCA and EDA are congruent.

You already have one pair of angles (<1 and <2) GIVEN congruent.

You know that A is the midpoint of arc CD, so what does that tell you about the measures of arcs CA and AD? They'd be congruent, because the midpoint of an arc divides it into two equal arcs. Now, if arcs CA and AD have the same degree measure, what can you conclude about the inscribed angles B and E?

Now you know something about TWO pairs of angles in the triangles. Finally,l look at chords CA and AD....those are two chords of the same circle and they cut off equal arcs. Does that allow you to make some conclusion about the two chords?

Ok....we know something about TWO angles and ONE side of the triangles. Is that enough to conclude that the triangles are congruent?

And if the triangles are congruent, you can conclude that each pair of corresponding sides must be congruent......

I hope these suggestions will help you complete the proof. It's not impossible at all! :)
 
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