In terms of p

[IloveManUtd]

If sin 50[sup:cp0szzn7]o[/sup:cp0szzn7] = p, then how do I express cos 50 in terms of p? So far I've figured out that it's in quadrant 1, meaning it is positive.

 

[BigGlenntheHeavy]

\(\displaystyle sin(90^0-\theta) \ = \ cos(\theta)\)

 

[Deleted member 4993]

If sin 50[sup:145igc9o]o[/sup:145igc9o] = p, then how do I express cos 50 in terms of p? So far I've figured out that it's in quadrant 1, meaning it is positive.

Use

\(\displaystyle sin^2(\theta)\ + \ cos^2(\theta)\ = \ 1\)