Someonewithoutanswers
New member
- Joined
- Nov 22, 2020
- Messages
- 6
Please tell us what methods you have learned, and show your attempt at one method, so we can see where you are stuck. That's how we work.
I haven't tried it yet, but the presence of both square root and cube root suggest making the substitution [MATH]u = \sqrt[6]{x}[/MATH], so that both are powers of u. The answer supports that idea.