How do I start solving an initial value problem such as this one:
y' = 2y^2 + xy^2, y(0) = 1
I've attempted to solve it but I get stuck at the first step...I try getting it in the form of dy/dx + Py = Q but I don't know how I would get a Q value in this case. This is what I get when I try getting it into the aforementioned form:
dy/dx + y^2*(2+x) = 0
Does that make any sense? Can anyone please step me through the process? Thanks a lot.
y' = 2y^2 + xy^2, y(0) = 1
I've attempted to solve it but I get stuck at the first step...I try getting it in the form of dy/dx + Py = Q but I don't know how I would get a Q value in this case. This is what I get when I try getting it into the aforementioned form:
dy/dx + y^2*(2+x) = 0
Does that make any sense? Can anyone please step me through the process? Thanks a lot.