Step 2: Let [math]u = x + 1[/math]
Step 3: Let [math]u = 3 ~ tan(v)[/math].
This gives [math]\int \dfrac{1}{(x^2 + 2x + 10)^2} ~ dx = \dfrac{1}{27} \int cos^2(v) ~ dv[/math]
Fill in the steps and you can take the integration from there.
Let us know if you need more help and show what you've done.
-Dan
Addendum: You could probably do this with partial fractions. I haven't looked at it that way yet.
This site uses cookies to help personalise content, tailor your experience and to keep you logged in if you register.
By continuing to use this site, you are consenting to our use of cookies.