D Deleted member 4993 Guest Oct 11, 2014 #2 Farzana17 said: s2x+1/x(x+3)dx Click to expand... If your problem is: \(\displaystyle \displaystyle{\int \dfrac{2x + 1}{x(x+3)} dx}\) use partial fraction to convert it to: \(\displaystyle \displaystyle{\int \dfrac{A}{x} dx \ + \ \int \dfrac{B}{x+3} dx}\) and continue....
Farzana17 said: s2x+1/x(x+3)dx Click to expand... If your problem is: \(\displaystyle \displaystyle{\int \dfrac{2x + 1}{x(x+3)} dx}\) use partial fraction to convert it to: \(\displaystyle \displaystyle{\int \dfrac{A}{x} dx \ + \ \int \dfrac{B}{x+3} dx}\) and continue....
