P pamw New member Joined Jan 10, 2007 Messages 8 Feb 9, 2007 #1 Hi, [integral]e^(3x)*arctan(e^(x))dx[/integral] Should I turn e^(3x) into (e^(x)^3)? Should I substitute? Help please!
Hi, [integral]e^(3x)*arctan(e^(x))dx[/integral] Should I turn e^(3x) into (e^(x)^3)? Should I substitute? Help please!
U Unco Senior Member Joined Jul 21, 2005 Messages 1,134 Feb 9, 2007 #2 Actually, e^(3x) = (e^(x))^3. But making a substitution using this is indeed a good place to start. Have a go at it yourself and show us how you go.
Actually, e^(3x) = (e^(x))^3. But making a substitution using this is indeed a good place to start. Have a go at it yourself and show us how you go.
skeeter Elite Member Joined Dec 15, 2005 Messages 3,204 Feb 10, 2007 #3 let \(\displaystyle \L t = e^x\) \(\displaystyle \L dt = e^x dx\) \(\displaystyle \L \int e^{3x} \arctan{(e^x)} dx =\) \(\displaystyle \L \int e^{2x} \arctan{(e^x)} e^x dx\) substitute ... \(\displaystyle \L \int t^2 \arctan{(t)} dt\) now use integration by parts ... \(\displaystyle \L u = \arctan{(t)}\) and \(\displaystyle \L dv = t^2 dt\)
let \(\displaystyle \L t = e^x\) \(\displaystyle \L dt = e^x dx\) \(\displaystyle \L \int e^{3x} \arctan{(e^x)} dx =\) \(\displaystyle \L \int e^{2x} \arctan{(e^x)} e^x dx\) substitute ... \(\displaystyle \L \int t^2 \arctan{(t)} dt\) now use integration by parts ... \(\displaystyle \L u = \arctan{(t)}\) and \(\displaystyle \L dv = t^2 dt\)