H hrr379 New member Joined Jun 9, 2012 Messages 17 Jun 17, 2012 #1 ∫tan^2(x) secx dx solution attempt ∫(sec^2(x)-1)sec x dx --> By following this route I am left with a ∫sec^3(x) dx infinitely. Is there a different approach some one can recommend?
∫tan^2(x) secx dx solution attempt ∫(sec^2(x)-1)sec x dx --> By following this route I am left with a ∫sec^3(x) dx infinitely. Is there a different approach some one can recommend?
D daon2 Full Member Joined Aug 17, 2011 Messages 999 Jun 17, 2012 #2 hrr379 said: ∫tan^2(x) secx dx solution attempt ∫(sec^2(x)-1)sec x dx --> By following this route I am left with a ∫sec^3(x) dx infinitely. Is there a different approach some one can recommend? Click to expand... \(\displaystyle \sec^3x\) can be integrated by parts, letting \(\displaystyle u=\sec x, dv = \sec^2 xdx\).
hrr379 said: ∫tan^2(x) secx dx solution attempt ∫(sec^2(x)-1)sec x dx --> By following this route I am left with a ∫sec^3(x) dx infinitely. Is there a different approach some one can recommend? Click to expand... \(\displaystyle \sec^3x\) can be integrated by parts, letting \(\displaystyle u=\sec x, dv = \sec^2 xdx\).
