rippletank
New member
- Joined
- Oct 9, 2014
- Messages
- 1
Solving the following problem for a general solution, I cannot understand how you get from the first step to the second.
d/dt(e^t^2) + 2ty(e^t^2) = 4e^-t^2(e^t^2)
d/dt(ye^t^2) = 4
I understand the right hand side, but I don't understand how the left hand side of the first line can be simplified to the left hand side of the second. That is what the book gives, but I must be missing something. Thanks for any help.
The original problem is
dy/dt = -2ty + 4e^-t^2 , y(0)=3
I know the integrating factor is e^t^2
d/dt(e^t^2) + 2ty(e^t^2) = 4e^-t^2(e^t^2)
d/dt(ye^t^2) = 4
I understand the right hand side, but I don't understand how the left hand side of the first line can be simplified to the left hand side of the second. That is what the book gives, but I must be missing something. Thanks for any help.
The original problem is
dy/dt = -2ty + 4e^-t^2 , y(0)=3
I know the integrating factor is e^t^2
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