M mindy88 New member Joined Apr 11, 2007 Messages 30 Aug 2, 2007 #1 What's the anti derivative of e^(2X+3)? i know that the formula for it is e^(kx) is (1/K)e^(kx) so...would it be 1/(2x+3) e^(2x+3)? thanks
What's the anti derivative of e^(2X+3)? i know that the formula for it is e^(kx) is (1/K)e^(kx) so...would it be 1/(2x+3) e^(2x+3)? thanks
pka Elite Member Joined Jan 29, 2005 Messages 11,978 Aug 2, 2007 #2 Try: \(\displaystyle \L \left( {\frac{1}{2}} \right)e^{(2x + 3)} .\) Do you see why?
M mindy88 New member Joined Apr 11, 2007 Messages 30 Aug 2, 2007 #3 so, i would use only the 2 because that's the derivative of 2x+3?
G galactus Super Moderator Staff member Joined Sep 28, 2005 Messages 7,203 Aug 2, 2007 #4 Hello MIndy: You can make a simple substitution and see it. \(\displaystyle \L\\\int{e^{2x+3}}dx\) Let \(\displaystyle \L\\u=2x+3, \;\ du=2dx, \;\ \frac{du}{2}=dx\) \(\displaystyle \L\\\frac{1}{2}\int{e^{u}}du\)
Hello MIndy: You can make a simple substitution and see it. \(\displaystyle \L\\\int{e^{2x+3}}dx\) Let \(\displaystyle \L\\u=2x+3, \;\ du=2dx, \;\ \frac{du}{2}=dx\) \(\displaystyle \L\\\frac{1}{2}\int{e^{u}}du\)
M mindy88 New member Joined Apr 11, 2007 Messages 30 Aug 3, 2007 #5 i didn't even think of using u-substitution thanks for the help