D dialalpha New member Joined Dec 13, 2009 Messages 2 Dec 13, 2009 #1 indefinite integral of (2x-3)/(x^3). I've tried u-substitution of (2x-3), but I get stuck pretty quick. Any pointers?
indefinite integral of (2x-3)/(x^3). I've tried u-substitution of (2x-3), but I get stuck pretty quick. Any pointers?
D daon Senior Member Joined Jan 27, 2006 Messages 1,284 Dec 13, 2009 #2 Re: Integration Break it into: \(\displaystyle 2\int \frac{x}{x^3}dx \,\,- \,\, 3\int \frac{1}{x^3}\) \(\displaystyle = 2\left( \int x^{-2}dx\right) - 3\left(\int x^{-3}dx\right)\)
Re: Integration Break it into: \(\displaystyle 2\int \frac{x}{x^3}dx \,\,- \,\, 3\int \frac{1}{x^3}\) \(\displaystyle = 2\left( \int x^{-2}dx\right) - 3\left(\int x^{-3}dx\right)\)
D dialalpha New member Joined Dec 13, 2009 Messages 2 Dec 13, 2009 #3 Re: Integration AH!, thank you, thank you.
