L lampat New member Joined Dec 14, 2011 Messages 16 Aug 22, 2016 #1 \(\displaystyle \displaystyle \int \sqrt{x+\sqrt{x^2+2}}dx\)
D Deleted member 4993 Guest Aug 22, 2016 #2 lampat said: \(\displaystyle \displaystyle \int \sqrt{x+\sqrt{x^2+2}}dx\) Click to expand... substitute x = √2 * tan(u) and continue....
lampat said: \(\displaystyle \displaystyle \int \sqrt{x+\sqrt{x^2+2}}dx\) Click to expand... substitute x = √2 * tan(u) and continue....
