I have managed to work out that I need to sub in the U and replace dx with du, here is my workings:
Let U = 2X - 1
du/dx = 2
dx = du/2
Rearrange to find X
X = 1/2(U + 1)
Therefore
∫x(2x-1)1/2 dx = ∫1/2(U+1)(U)1/2 du/2 = 1/2 * 1/2 ∫(U + 1)(U)1/2 du = 1/4∫U3/2 + U1/2 du
therefore 1/4[2U5/2/5 + 2U3/2/3] which simplifies to U5/2/10 + U3/2/6
but I the answer is this:
1/15(3x+1)(2x-1)3/2 + c
How do I get to this result!?
Let U = 2X - 1
du/dx = 2
dx = du/2
Rearrange to find X
X = 1/2(U + 1)
Therefore
∫x(2x-1)1/2 dx = ∫1/2(U+1)(U)1/2 du/2 = 1/2 * 1/2 ∫(U + 1)(U)1/2 du = 1/4∫U3/2 + U1/2 du
therefore 1/4[2U5/2/5 + 2U3/2/3] which simplifies to U5/2/10 + U3/2/6
but I the answer is this:
1/15(3x+1)(2x-1)3/2 + c
How do I get to this result!?