Intergration question

[mark]

intergrate:

cosh(lnx) dx

i tried using u-substition

u = lnx

du = 1/x dx

dx = xdu

but that doenst get me anywere

 

[Gene]

Not even if you know that x=e^u?

 

[mark]

i know that x = e^u

but then that gives me

intergration of e^u coshu du which makes the problem more complicated

 

[Gene]

But it simplifies again because
cosh(u)=(e^u+e^-u)/2

 

[mark]

i didnt see that, thanks for you help