intermedicate algebra

[Gail Price]

tell me if I did this problem correctly please
?2x-?2x-12=6
2x-12+6=0
-6=0=+6
2x=6
-2=6+12
x=18
?2x+18-2
-2=16
x=16

 

[Deleted member 4993]

tell me if I did this problem correctly please
?2x-?2x-12=6 <<<< Did you post the problem correctly? Because ?2x-?2x = 0 ? then you are left with -12 = 6 ? which is inconsistent
2x-12+6=0
-6=0=+6
2x=6
-2=6+12
x=18
?2x+18-2
-2=16
x=16

 

[Gail Price]

Since you can not find a square root sign that will post in this forumor any other for that fact, it is really not displayed correctly for clarification.
?2x- ?2x-12=6
?2x-12 this is under one square root symbol = 6 the ?2x- in in the front of the 2x-12. Do you understand?

 

[Gail Price]

Here is one I worked out. I do not do welll in Math so excuse me please.

Problem: (w-3)^2=16

My work
(w-3) (w-3) = 16
w^-3w
-3w+9=16
w^2-6w+9=16
-9
w^2-6w=7
6
w^2-w=13
w=13
Does this look crazy or what?

 

[Deleted member 4993]

Here is one I worked out. I do not do welll in Math so excuse me please.

Problem: (w-3)^2=16

(w-3)[sup:3nqsxau2]2[/sup:3nqsxau2] - 4[sup:3nqsxau2]2[/sup:3nqsxau2] = 0

[(w-3)+4][(w-3)-4] = 0

Can you finish from here....

My work
(w-3) (w-3) = 16
w^-3w
-3w+9=16
w^2-6w+9=16
-9
w^2-6w=7
6
w^2-w=13
w=13<<<<<<< Incorrect
Does this look crazy or what?

 

[JeffWest]

See the post that you made on Feb 20th. I replied with a good explanation of this problem.

Enjoy