Interval of Convergence

lala_doda

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Joined
Jan 14, 2012
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Find the interval of convergence for the power series:
infinity
Sigma (1/(3n))((x-1)n)
n=0
I got that the radius is 4 and since it is centered around 1 the interval should be (-3,5), am I right?
 
Find the interval of convergence for the power series: infinity
Sigma (1/(3n))((x-1)n)
n=0
I got that the radius is 4 and since it is centered around 1 the interval should be (-3,5), am I right?
You best think again there.
Using the absolute root test we get \(\displaystyle \dfrac{|x-1|}{3}<1\) as the basic set of convergence.
Now you need to test endpoints.
 
You best think again there.
Using the absolute root test we get \(\displaystyle \dfrac{|x-1|}{3}<1\) as the basic set of convergence.
Now you need to test endpoints.

oh okay, so it would be (-2,4), correct?
 
Yes, that is correct. The radius of convergence is 3.
 
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