Inverse function for h(x) = x + 3 / 4x - 2

[youknowitsucka]

h(x)= x+3/4x-2

i start out good, but then i always end up getting stuck..i'd love some help!

 

[ilaggoodly]

so you have
\(\displaystyle \L \frac{x+3}{4x-2} = y\)
invert
\(\displaystyle \L \frac{y+3}{4y-2} = x\)
simplify!
\(\displaystyle \L y+3 = x(4y-2)\)

\(\displaystyle \L y = 4xy - 2x - 3\)

\(\displaystyle \L y-4xy = -2x -3\)

\(\displaystyle \L y(1-4x) = -2x -3\)

\(\displaystyle \L y = \frac{-2x-3}{1-4x}\)

 

[youknowitsucka]

thanks soo much..i figured out where i screwed up!