It appears that you know very little about the logarithm function.Find the inverse of y = log x ^a ? Log y = a log x , log x =logy/a , this is where I got stuck . Thanks.
If y= log x^a then y= alog(x) NOT "log y". so y/a= log(x). Assuming that is the natural logarithm x= e^(y/a).Find the inverse of y = log x ^a ? Log y = a log x , log x =logy/a , this is where I got stuck . Thanks.