N namitha New member Joined Oct 15, 2016 Messages 1 Oct 15, 2016 #1 If x1,x2,x3,x4 are the roots of the equation x4-x3 sin2(Beta)+x2 cos 2(Beta)-x cos(Beta)-sin(Beta)=0 then summation i=1 to 4 of tan^-1 xi is ?
If x1,x2,x3,x4 are the roots of the equation x4-x3 sin2(Beta)+x2 cos 2(Beta)-x cos(Beta)-sin(Beta)=0 then summation i=1 to 4 of tan^-1 xi is ?
D Deleted member 4993 Guest Oct 15, 2016 #2 namitha said: If x1,x2,x3,x4 are the roots of the equation x4-x3 sin2(Beta)+x2 cos 2(Beta)-x cos(Beta)-sin(Beta)=0 then summation i=1 to 4 of tan^-1 xi is ? Click to expand... What are the real roots of: x4-= x * (x3 - 1) = x * (x - 1)(x2 + x + 1) Continue.... Last edited by a moderator: Oct 15, 2016
namitha said: If x1,x2,x3,x4 are the roots of the equation x4-x3 sin2(Beta)+x2 cos 2(Beta)-x cos(Beta)-sin(Beta)=0 then summation i=1 to 4 of tan^-1 xi is ? Click to expand... What are the real roots of: x4-= x * (x3 - 1) = x * (x - 1)(x2 + x + 1) Continue....
stapel Super Moderator Staff member Joined Feb 4, 2004 Messages 16,550 Oct 15, 2016 #3 namitha said: ...the equation x4-x3 sin2(Beta)+x2 cos 2(Beta)-x cos(Beta)-sin(Beta)=0... Click to expand... Are the two lines above actually supposed to be one? In particular, is "the equation" supposed to be as follows? . . . . .x4 - x3 sin2(Beta) + x2 cos 2(Beta) - x cos(Beta) - sin(Beta) = 0 When you reply, please include a clear listing of your thoughts and efforts so far, so we can see where you're needing assistance. Thank you!
namitha said: ...the equation x4-x3 sin2(Beta)+x2 cos 2(Beta)-x cos(Beta)-sin(Beta)=0... Click to expand... Are the two lines above actually supposed to be one? In particular, is "the equation" supposed to be as follows? . . . . .x4 - x3 sin2(Beta) + x2 cos 2(Beta) - x cos(Beta) - sin(Beta) = 0 When you reply, please include a clear listing of your thoughts and efforts so far, so we can see where you're needing assistance. Thank you!