ionized lithium

[logistic_guy]

Calculate the ionization energy of doubly ionized lithium, $\displaystyle \text{Li}^{2+}$, which has $\displaystyle Z = 3$.

 

[khansaheb]

Calculate the ionization energy of doubly ionized lithium, $\displaystyle \text{Li}^{2+}$, which has $\displaystyle Z = 3$.

Please show us what you have tried and exactly where you are stuck.

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[logistic_guy]

Please show us what you have tried and exactly where you are stuck.

Please follow the rules of posting in this forum, as enunciated at:

READ BEFORE POSTING​

Please share your work/thoughts about this problem

Thank you Sir khan.

We start with the electron energy formula.

$\displaystyle E_n = -\frac{Z^2(13.6 \ \text{eV})}{n^2}$

The goal is to remove one electron from the nucleus completely, then:

The ionization energy $\displaystyle = E_{\infty} - E_1 = 0 - \left(-\frac{3^2(13.6 \ \text{eV})}{1^2}\right) = 122 \ \text{eV}$