Is this angle less than or equal to another angle

[lalt]

The question is sec40 less than or equal to csc50. The answer is that they are equal but I don't get how

 

[stapel]

The question is sec40 less than or equal to csc50.

This is not a question; it is a statement. Were there any instructions that went with this statement?

The answer is that they are equal but I don't get how

What identities have you been given so far?

 

[topsquark]

The question is sec40 less than or equal to csc50. The answer is that they are equal but I don't get how

First, convert to sine and cosine:
[imath]sec(40) = \dfrac{1}{cos(40)}[/imath]

[imath]csc(50) = \dfrac{1}{sin(50)}[/imath]

Thus, the question is, "How do cos(40) and sin(50) compare?" (And, yes, they are indeed equal.)

Can you finish from here?

-Dan

 

[Steven G]

if a+b = 90, a>=0 and b>0, then sina=sinb. Therefore 1/sina=1/cosb so csca=secb.

 

[topsquark]

if a+b = 90, a>=0 and b>0, then sina=sinb. Therefore 1/sina=1/cosb so csca=secb.

You mean sin a = cos b...

-Dan

 

[khansaheb]

if a+b = 90, a>=0 and b>0, then sina=sinb.

Corner ..... Corner......

 

[lookagain]

The question is sec40 less than or equal to csc50. The answer is that they are equal but I don't get how

The question: "Is sec(40 degrees) less than or equal to csc(50 degrees)?"

These are trigonometric functions, so the angles should be inside grouping
symbols. In this problem you are not working with radians, so you should have the
degree symbol with the number, or have the word "degrees" with the number.

In my opinion, if you have handy access to the degree symbol, it is more compact
in writing, and it looks better than my illustration in my top line.