J Jen123 New member Joined Oct 21, 2006 Messages 31 Jul 4, 2007 #1 How many ways can 5 students be chosen from a group of 4 juniors and 6 seniors to be on the prom committee if exactly 3 students must be seniors? 10! / 3! 3! 4! = 604800 Is this correct or should I be doing the equation as a permutation.
How many ways can 5 students be chosen from a group of 4 juniors and 6 seniors to be on the prom committee if exactly 3 students must be seniors? 10! / 3! 3! 4! = 604800 Is this correct or should I be doing the equation as a permutation.
pka Elite Member Joined Jan 29, 2005 Messages 11,978 Jul 4, 2007 #2 \(\displaystyle { 6 \choose 3}{ 4 \choose 2} = \frac{{6!}}{{\left( {3!} \right)\left( {3!} \right)}}\frac{{4!}}{{\left( {2!} \right)\left( {2!} \right)}}\)
\(\displaystyle { 6 \choose 3}{ 4 \choose 2} = \frac{{6!}}{{\left( {3!} \right)\left( {3!} \right)}}\frac{{4!}}{{\left( {2!} \right)\left( {2!} \right)}}\)
