is this right?

maggie0160

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Oct 19, 2005
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Which of the lines below is a horizontal asymptote for the graph of
y = (x^3 - 7x - 2)/(2x^3 - 1)

= y = 1 ?
 
Hello, maggie0160!

Which of the lines below is a horizontal asymptote for the graph of
y = (x<sup>3</sup> - 7x - 2)/(2x<sup>3</sup> - 1)

y = 1 ? . . . . no
A horizontal asymptote is found by taking the limit of y as x "becomes infinite".

. . . . . . . . . . . . . . . . . . . . . . . . .1 - 7/x<sup>2</sup> - 2/x<sup>3</sup>
Divide top and bottom by x<sup>3</sup>: . ------------------
. . . . . . . . . . . . . . . . . . . . . . . . . . . 2 - 1/x<sup>3</sup>

Now take the limit . . .
 
Look at Horizontal Asymptotes in the blue area to the right.
horizontal asymptotes are the limit as x-> oo
 
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