it's been a while for me can you help a-b+c/r^2+8=t solve

M

man1912

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Nov 27, 2007
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i need to solve for c the equation is a-b+c all over r squared+8 =T now i need c on it's own i came up with c=(t-a+b)(r squared-8) it just doesn't seem right to me.
 
Not quite. Show us what you've done and we'll help point out any errors.

\(\displaystyle \frac{a - b + c}{r^{2} + 8} = T\)

Start by getting rid of the denominator (r[sup:2cp5koiv]2[/sup:2cp5koiv] + 8).
 
well for r^2+8 i would multiply it to bring it to the other side so it would be a-b+c=T(r^2+8) that's what i did.
 
Alright, now keep going. You want c all by itself, so how do you get rid of a and -b?
 
then i would subtrack a and add b so to me it would look like this c=T(r^2-8)-a+b it still does seem right. this is not how i went about it befor. i tryed to get ride of the a-b first. i now see that i can't do that. oops :lol: is this right then?
 
Yep, it's right now :wink:

And yes, you can't just subtract numbers off the numerator without involving the denominator.
 
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