DavidNyan10
New member
- Joined
- Oct 25, 2023
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I know I'm 8 years too late [for this thread], but I've came up with my own quadratic equation:
[math]ax^2+bx+c\:=\:0\hspace{1in}a,\:b,\:c\:\in\:\mathbb{R} \\\\ x\:=\:-\frac{c}{b}+a\left[\frac{-b\pm\sqrt{b^2-4ac}}{2a^2}+\frac{c}{ab}\right][/math]
[math]ax^2+bx+c\:=\:0\hspace{1in}a,\:b,\:c\:\in\:\mathbb{R} \\\\ x\:=\:-\frac{c}{b}+a\left[\frac{-b\pm\sqrt{b^2-4ac}}{2a^2}+\frac{c}{ab}\right][/math]
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